r^2+4r+4=2r

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Solution for r^2+4r+4=2r equation: 



r^2+4r+4=2r

We move all terms to the left:

r^2+4r+4-(2r)=0

We add all the numbers together, and all the variables

r^2+2r+4=0

a = 1; b = 2; c = +4;
Δ = b2-4ac
Δ = 22-4·1·4
Δ = -12
Delta is less than zero, so there is no solution for the equation

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